Question

a car goes from traveling at 23 m/s to 29 m/s at an acceleration of 3 m/s². how long did the change in velocity take? t = ?s remember: a = \frac{\delta v}{t}

Explanation:

Step1: Identify given values

Initial velocity $u = 23\ m/s$, final velocity $v=29\ m/s$, acceleration $a = 3\ m/s^{2}$.

Step2: Calculate change in velocity

$\Delta v=v - u=29 - 23=6\ m/s$.

Step3: Rearrange acceleration formula for time

Given $a=\frac{\Delta v}{t}$, we can solve for $t$ as $t=\frac{\Delta v}{a}$.

Step4: Substitute values to find time

$t=\frac{6}{3}=2\ s$.

Answer:

$2$