Question

a cart moves along a track at a velocity of 3.5 cm/s. when a force is applied to the cart, its velocity increases to 8.2 cm/s. if it takes the cart 1.5 seconds to reach 8.2 cm/s, what is the acceleration of the cart? round your answer to the nearest tenth. cm/s²

Explanation:

Step1: Identify initial and final velocities and time

Initial velocity $u = 3.5$ cm/s, final velocity $v = 8.2$ cm/s, time $t=1.5$ s.

Step2: Use acceleration formula

The formula for acceleration $a=\frac{v - u}{t}$. Substitute the values: $a=\frac{8.2 - 3.5}{1.5}$.

Step3: Calculate the numerator

$8.2-3.5 = 4.7$ cm/s.

Step4: Calculate the acceleration

$a=\frac{4.7}{1.5}\approx3.1$ cm/s².

Answer:

$3.1$