Question

a certain noninverting amplifier has an ri of 11 kω and an rf of 109 kω. the closed - loop gain is
answer:

Explanation:

Step1: Recall noninverting gain formula

The closed-loop gain \(A_v\) of a noninverting amplifier is given by:
$$A_v = 1 + \frac{R_f}{R_i}$$

Step2: Substitute given values

Substitute \(R_f = 109\ \text{k}\Omega\) and \(R_i = 11\ \text{k}\Omega\):
$$A_v = 1 + \frac{109}{11}$$

Step3: Calculate the fraction

Compute the division:
$$\frac{109}{11} \approx 9.909$$

Step4: Sum to find gain

Add 1 to the result:
$$A_v = 1 + 9.909 \approx 11$$

Answer:

11