Question

if cf = 3t + 2 and ef = 10t - 89, find the value of t in parallelogram bcde.

Explanation:

Step1: Use property of parallelogram

In a parallelogram, the diagonals bisect each other. So $CF = EF$. We set up the equation $3t + 2=10t - 89$.

Step2: Rearrange the equation

Subtract $3t$ from both sides: $2 = 10t-3t - 89$, which simplifies to $2 = 7t - 89$.

Step3: Solve for t

Add 89 to both sides: $2 + 89=7t$, so $91 = 7t$. Then divide both sides by 7: $t=\frac{91}{7}=13$.

Answer:

$13$