Question

check here for instructional material to complete this problem. rewrite the expression using exponents. 7·3·3·3·3·3 7·3·3·3·3·3 = 3^□ ·7^□ (type whole numbers.)

Explanation:

Step1: Count the number of 3s

The expression \(7 \cdot 3 \cdot 3 \cdot 3 \cdot 3 \cdot 3\) has one 7 and five 3s.

Step2: Rewrite using exponents

Using the exponent rule \(a \cdot a \cdot \dots \cdot a\) (n times) \(= a^n\), the five 3s can be written as \(3^5\) and the 7 remains as \(7^1\) (since there's one 7). So the expression becomes \(3^5 \cdot 7^1\).

Answer:

For the first blank (exponent of 3): 5, for the second blank (exponent of 7): 1. So the filled expression is \(3^{\boldsymbol{5}} \cdot 7^{\boldsymbol{1}}\)