Question

choose the sum that is greater than 9. $8\frac{2}{6}+\frac{4}{6}$ $8\frac{3}{6}+\frac{2}{6}$ $8\frac{4}{6}+\frac{5}{6}$ $8\frac{5}{6}+\frac{1}{6}$

Explanation:

Step1: Calculate first sum

$8\frac{2}{6} + \frac{4}{6} = 8 + \frac{2+4}{6} = 8 + 1 = 9$

Step2: Calculate second sum

$8\frac{3}{6} + \frac{2}{6} = 8 + \frac{3+2}{6} = 8 + \frac{5}{6} = 8\frac{5}{6}$

Step3: Calculate third sum

$8\frac{4}{6} + \frac{5}{6} = 8 + \frac{4+5}{6} = 8 + \frac{9}{6} = 8 + 1\frac{3}{6} = 9\frac{1}{2}$

Step4: Calculate fourth sum

$8\frac{5}{6} + \frac{1}{6} = 8 + \frac{5+1}{6} = 8 + 1 = 9$

Step5: Identify sum >9

Compare results: $9$, $8\frac{5}{6}$, $9\frac{1}{2}$, $9$. Only $9\frac{1}{2}$ is greater than 9.

Answer:

$8\frac{4}{6} + \frac{5}{6}$