Question

choose the sum that is greater than 5.
$4\frac{1}{8}+\frac{5}{8}$
$4\frac{3}{8}+\frac{3}{8}$
$4\frac{5}{8}+\frac{7}{8}$
$4\frac{6}{8}+\frac{1}{8}$

Explanation:

Step1: Calculate first sum

$4\frac{1}{8} + \frac{5}{8} = 4 + \frac{1+5}{8} = 4 + \frac{6}{8} = 4\frac{3}{4}$

Step2: Calculate second sum

$4\frac{3}{8} + \frac{3}{8} = 4 + \frac{3+3}{8} = 4 + \frac{6}{8} = 4\frac{3}{4}$

Step3: Calculate third sum

$4\frac{5}{8} + \frac{7}{8} = 4 + \frac{5+7}{8} = 4 + \frac{12}{8} = 4 + 1\frac{4}{8} = 5\frac{1}{2}$

Step4: Calculate fourth sum

$4\frac{6}{8} + \frac{1}{8} = 4 + \frac{6+1}{8} = 4\frac{7}{8}$

Step5: Compare sums to 5

$4\frac{3}{4} < 5$, $4\frac{3}{4} < 5$, $5\frac{1}{2} > 5$, $4\frac{7}{8} < 5$

Answer:

$4\frac{5}{8} + \frac{7}{8}$