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Question
in circle d, angle adc measures (7x + 2)°. arc ac measures (8x - 8)°. what is the measure of ∠abc? 36° 43° 72° 144°
Step1: Recall central - inscribed angle relationship
The measure of a central angle is equal to the measure of its intercepted arc. So, $\angle ADC$ (central angle) and arc $AC$ are related as $7x + 2=8x - 8$.
Step2: Solve for $x$
Subtract $7x$ from both sides of the equation $7x + 2=8x - 8$:
$2=x - 8$.
Then add 8 to both sides: $x=10$.
Step3: Find the measure of arc $AC$
Substitute $x = 10$ into the expression for arc $AC$: $8x-8=8\times10 - 8=72^{\circ}$.
Step4: Recall the inscribed - arc relationship
The measure of an inscribed angle is half the measure of its intercepted arc. $\angle ABC$ is an inscribed angle and arc $AC$ is its intercepted arc. So, $m\angle ABC=\frac{1}{2}m\overset{\frown}{AC}$.
Since $m\overset{\frown}{AC}=72^{\circ}$, then $m\angle ABC = 36^{\circ}$.
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A. $36^{\circ}$