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if: cj = 3x + 6, ct = 37, and jt = 3x + 7, find jt.

Question

if: cj = 3x + 6, ct = 37, and jt = 3x + 7, find jt.

Explanation:

Step1: Use segment - addition postulate

Since $CT = CJ+JT$, we substitute the given expressions: $37=(3x + 6)+(3x + 7)$.

Step2: Simplify the right - hand side

Combine like terms: $37 = 6x+13$.

Step3: Solve for $x$

Subtract 13 from both sides: $37−13 = 6x$, so $24 = 6x$. Then divide both sides by 6: $x = 4$.

Step4: Find $JT$

Substitute $x = 4$ into the expression for $JT$. Since $JT=3x + 7$, then $JT=3\times4 + 7$.
Calculate $3\times4+7=12 + 7=19$.

Answer:

19