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classwork - 10 - 6 solve for y. 1) 2x - 3y = 27 -2x -2x -3y = 2x - 27 y…

Question

classwork - 10 - 6 solve for y. 1) 2x - 3y = 27 -2x -2x -3y = 2x - 27 y = 2/3x - 9 2) 1/4y + 9x = 12 1/4y = -9x + 12 y = -36x + 48 3) the formula for the area of a rectangle is a = lw a) solve for w w = b) if the area is 150 sq. ft. & the l is 25 ft., find the w

Explanation:

Step1: Solve 2x - 3y = 27 for y

Subtract 2x from both sides:
-3y=2x - 27
Then divide by - 3:
y = $\frac{2x-27}{-3}=\frac{2}{3}x - 9$

Step2: Solve $\frac{1}{4}y+9x = 12$ for y

Subtract 9x from both sides:
$\frac{1}{4}y=-9x + 12$
Multiply both sides by 4:
y=-36x + 48

Step3: Solve A = Lw for w

Divide both sides by L:
w=$\frac{A}{L}$

Step4: Find w when A = 150 and L = 25

Substitute A = 150 and L = 25 into w=$\frac{A}{L}$:
w=$\frac{150}{25}=6$

Answer:

  1. y=$\frac{2}{3}x - 9$
  2. y=-36x + 48
  3. A) w=$\frac{A}{L}$

B) w = 6