QUESTION IMAGE
Question
common core math ii a-cr - rla
what is the vertex of $g(x)=-3x^2 + 18x + 2?$
$(3,-25)$
$(-3,-25)$
$(3,29)$
$(-3,29)$
Step1: Find x-coordinate of vertex
For quadratic $g(x)=ax^2+bx+c$, $x = -\frac{b}{2a}$. Here $a=-3$, $b=18$:
$x = -\frac{18}{2(-3)} = \frac{-18}{-6} = 3$
Step2: Find y-coordinate of vertex
Substitute $x=3$ into $g(x)$:
$g(3) = -3(3)^2 + 18(3) + 2 = -3(9) + 54 + 2 = -27 + 54 + 2 = 29$
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(3, 29)