Question

a. complete the equation that represents the hanger.
3$square$(x + 2$square$) = 11$square$
b. solve the equation.
x = $square$
c. complete the statements about how you could solve the equation using the hanger.
divide both sides by $square$ to get a circle labeled x and a rectangle labeled 2 on the left, and a rectangle labeled $square$ on the right. then subtract $square$ from each side to get a circle on the left and rectangle with $square$ on the right.

Explanation:

Step1: Set up the hanger equation

Assuming the hanger has 3 groups of $(x+2)$ balancing 11, the equation is $3(x + 2) = 11$

Step2: Expand the left side

$3x + 6 = 11$

Step3: Isolate the variable term

Subtract 6 from both sides: $3x = 11 - 6 = 5$

Step4: Solve for x

Divide by 3: $x = \frac{5}{3}$

Step5: Fill hanger solution steps

First divide both sides by 3: left side becomes $x+2$, right side becomes $\frac{11}{3}$. Then subtract 2 (or $\frac{6}{3}$) from each side: left side is $x$, right side is $\frac{5}{3}$.

Answer:

a. $3(x + 2) = 11$
b. $x = \frac{5}{3}$
c. Divide both sides by $\boldsymbol{3}$ to get a circle labeled x and a rectangle labeled 2 on the left, and a rectangle labeled $\boldsymbol{\frac{11}{3}}$ on the right. Then subtract $\boldsymbol{2}$ from each side to get a circle on the left and rectangle with $\boldsymbol{\frac{5}{3}}$ on the right.