Question

complete the equations.
489 = 4 hundreds + 8 tens + 9 ones
489 = 0 hundreds + \boxed{} tens + 9 ones
489 = 0 hundreds + 0 tens + \boxed{} ones

Explanation:

Step1: Analyze the second equation

We know that \(489 = 0\times100 + \text{[tens]}\times10 + 9\times1\). First, calculate \(0\times100 = 0\) and \(9\times1 = 9\). Then, let the number of tens be \(x\). So the equation becomes \(489 = 0 + 10x + 9\). Subtract 9 from both sides: \(489 - 9 = 10x\), which is \(480 = 10x\). Then \(x=\frac{480}{10}=48\).

Step2: Analyze the third equation

We know that \(489 = 0\times100 + 0\times10 + \text{[ones]}\times1\). Let the number of ones be \(y\). So the equation is \(489 = 0 + 0 + y\times1\), which means \(y = 489\).

Answer:

For the second equation, the number of tens is \(48\). For the third equation, the number of ones is \(489\).

So the completed equations are:
\(489 = 0\) hundreds \(+\boldsymbol{48}\) tens \(+ 9\) ones
\(489 = 0\) hundreds \(+ 0\) tens \(+\boldsymbol{489}\) ones