QUESTION IMAGE
Question
complete the following proofs.
1.
given: - 5(x + 4)=70.
prove: x = - 18.
statements reasons
- 5(x + 4)=70
-5x - 20 = 70
- 5x - 20 + 20 = 70 + 20
- 5x = 90
\\(\frac{-5x}{-5}=\frac{90}{-5}\\)
x = - 18
- given: point s is between points r and t and rs = 2x - 11, st = 9, and rt = x + 5
prove: x = 7
statements reasons
- 1.
- rs + st = rt 2.
- rs = 2x - 11,st = 9, and rt = x + 5 3.
- 4. substitution
- 5. substitution
- x - 2 = 5 6.
- 7.
geometry unit 1.1
Step1: Expand the left - hand side
Using the distributive property \(a(b + c)=ab+ac\), for \(-5(x + 4)\), we get \(-5x-20 = 70\).
Step2: Add 20 to both sides
To isolate the term with \(x\), we use the addition property of equality. \(-5x-20 + 20=70 + 20\), which simplifies to \(-5x=90\).
Step3: Divide both sides by - 5
Using the division property of equality, \(\frac{-5x}{-5}=\frac{90}{-5}\), so \(x=-18\).
For the second problem:
Step1: State the given fact
Point \(S\) is between points \(R\) and \(T\). Reason: Given.
Step2: Use the segment addition postulate
If \(S\) is between \(R\) and \(T\), then \(RS + ST=RT\). Reason: Segment addition postulate.
Step3: State the given lengths
\(RS = 2x-11\), \(ST = 9\), and \(RT=x + 5\). Reason: Given.
Step4: Substitute the lengths into the equation
\((2x-11)+9=x + 5\). Reason: Substitution.
Step5: Simplify the left - hand side
Combine like terms: \(2x-11 + 9=2x-2\), so \(2x-2=x + 5\). Reason: Simplification.
Step6: Subtract \(x\) from both sides
\(2x-x-2=x-x + 5\), which gives \(x-2=5\). Reason: Subtraction property of equality.
Step7: Add 2 to both sides
\(x-2+2=5+2\), so \(x = 7\). Reason: Addition property of equality.
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
1.
| Statements | Reasons |
|---|---|
| \(-5x-20 = 70\) | Distributive property |
| \(-5x-20 + 20=70 + 20\) | Addition property of equality |
| \(-5x=90\) | Simplification |
| \(\frac{-5x}{-5}=\frac{90}{-5}\) | Division property of equality |
| \(x=-18\) | Simplification |
2.
| Statements | Reasons |
|---|---|
| \(RS + ST=RT\) | Segment addition postulate |
| \(RS = 2x-11\), \(ST = 9\), \(RT=x + 5\) | Given |
| \((2x-11)+9=x + 5\) | Substitution |
| \(2x-2=x + 5\) | Simplification |
| \(x-2=5\) | Subtraction property of equality |
| \(x = 7\) | Addition property of equality |