Question

complete the following statement. use the integers that are closest to the number in the middle.
\square < \sqrt{112} < \square

Explanation:

Step1: Find perfect squares around 112

We know that \(10^2 = 100\) and \(11^2 = 121\). Also, \(100<112<121\).

Step2: Take square roots

Taking square roots of all parts of the inequality \(100 < 112 < 121\), we get \(\sqrt{100}<\sqrt{112}<\sqrt{121}\). Since \(\sqrt{100} = 10\) and \(\sqrt{121}=11\), we have \(10 < \sqrt{112}<11\).

Answer:

\(10 < \sqrt{112}<11\) (So the first box is 10 and the second box is 11)