Question

consider the diagram and the proof below. given: in △abc, ad ⊥ bc prove: $\frac{sin(b)}{b}=\frac{sin(c)}{c}$ what is the missing statement in step 6? o b = c o $\frac{h}{b}=\frac{h}{c}$ o $csin(b)=bsin(c)$ o $bsin(b)=csin(c)$

Explanation:

Step1: Recall previous steps

In step 3, we have $c\sin(B)=h$ and in step 5, we have $b\sin(C)=h$.

Step2: Use substitution property

Since both $c\sin(B)$ and $b\sin(C)$ are equal to $h$, we can substitute. So $c\sin(B)=b\sin(C)$.

Answer:

$c\sin(B)=b\sin(C)$