Question

consider the following function.

h(x)=\frac{3}{5x^{3}}

step 2 of 2: find two points on the graph of this function, other than the origin, that fit within the given (-10,10) by (-10,10) grid. express each coordinate as an integer or simplified fraction, or round to four decimal places as necessary.

answer

Explanation:

Step1: Choose an x - value

Let's choose \(x = 1\).

Step2: Calculate the corresponding y - value

Substitute \(x = 1\) into \(h(x)=\frac{3}{5x^{3}}\). Then \(h(1)=\frac{3}{5\times1^{3}}=\frac{3}{5}= 0.6\). So one point is \((1,0.6)\).

Step3: Choose another x - value

Let's choose \(x=-1\).

Step4: Calculate the corresponding y - value

Substitute \(x = - 1\) into \(h(x)=\frac{3}{5x^{3}}\). Then \(h(-1)=\frac{3}{5\times(-1)^{3}}=-\frac{3}{5}=-0.6\). So another point is \((-1,-0.6)\).

Answer:

\((1,0.6),(-1,-0.6)\)