Question

consider the following inequality: -3z - 2 > 16 step 1 of 2: write the solution using interval notation. answer 2 points

Explanation:

Step1: Isolate the variable term

Add 2 to both sides:
$$-3z - 2 + 2 > 16 + 2$$
$$-3z > 18$$

Step2: Solve for z, reverse inequality

Divide by -3, flip the sign:
$$\frac{-3z}{-3} < \frac{18}{-3}$$
$$z < -6$$

Step3: Convert to interval notation

All real numbers less than -6:
$$(-\infty, -6)$$

Answer:

$(-\infty, -6)$