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construct ∠d so that ∠d≅∠c. with the same compass setting, put the comp…

Question

construct ∠d so that ∠d≅∠c.
with the same compass setting, put the compass point on c. draw an arc and label its point of intersection with the construction in the first step as k.
open the compass to length ab and put the compass point on c. draw an arc and label its point of intersection with the construction in the first step as r.
what is the fourth step of the construction?
a open the compass to length ab. put the compass point on r and draw another arc that intersects the arc constructed in the previous step. label the intersection t.
b open the compass to length ab. put the compass point on a and draw another arc that intersects the arc constructed in the previous step. label the intersection t.
c with the same compass setting as the previous step, put the compass point on r and draw another arc that intersects the arc constructed in the previous step. label the intersection t
d with the same compass setting as the previous step, put the compass point on a and draw another arc that intersects the arc constructed in the previous step. label the intersection t.
what is the final step of the construction?
a draw (overrightarrow{ct}).
b draw (overrightarrow{dt}).
c draw (overrightarrow{bt}).
d draw (overrightarrow{at}).

Explanation:

Brief Explanations

When constructing an angle congruent to a given angle, after some initial arc - drawing steps, in the fourth step, with the same compass setting as the previous step, we put the compass point on the intersection point (here R) and draw another arc to get the intersection point T. For the final step, we draw a ray from the vertex of the new angle (D) through the intersection point T.

Answer:

What is the fourth step of the construction?
C. With the same compass setting as the previous step, put the compass point on R and draw another arc that intersects the arc constructed in the previous step. Label the intersection T.
What is the final step of the construction?
B. Draw $\overrightarrow{DT}$.