Question

the coordinates of the vertices of a triangle are n (-1,-3), p (-4,-3), and q (-3,-1). triangle npq is rotated 270° counterclockwise with the origin as the center of rotation to create triangle npq. which graph correctly shows triangle npq?

Explanation:

Step1: Recall rotation rule

The rule for a 270 - counter - clockwise rotation about the origin is $(x,y)\to(y, - x)$.

Step2: Apply rule to point N

For $N(-1,-3)$, after rotation $N'$ has coordinates $(-3,1)$.

Step3: Apply rule to point P

For $P(-4,-3)$, after rotation $P'$ has coordinates $(-3,4)$.

Step4: Apply rule to point Q

For $Q(-3,-1)$, after rotation $Q'$ has coordinates $(-1,3)$.

Answer:

You need to check which of the given graphs has vertices at $N'(-3,1)$, $P'(-3,4)$ and $Q'(-1,3)$. Without seeing the full - scale options clearly, you can use these coordinates to identify the correct graph.