Question

1. copper has a specific heat of 0.385 j/(g×°c). a piece of copper absorbs 5000 j of energy and undergoes a temperature change from 100 °c to 200 °c. what is the mass of the piece of copper? round to the nearest tenth.

Explanation:

Step1: Identify the formula

The heat - energy formula is $Q = mc\Delta T$, where $Q$ is the heat energy, $m$ is the mass, $c$ is the specific heat, and $\Delta T$ is the change in temperature.

Step2: Calculate the change in temperature

$\Delta T=T_2 - T_1=200^{\circ}C - 100^{\circ}C = 100^{\circ}C$

Step3: Rearrange the formula to solve for mass

$m=\frac{Q}{c\Delta T}$

Step4: Substitute the given values

$Q = 5000J$, $c = 0.385J/(g\cdot^{\circ}C)$, and $\Delta T=100^{\circ}C$. Then $m=\frac{5000J}{0.385J/(g\cdot^{\circ}C)\times100^{\circ}C}$

Step5: Calculate the mass

$m=\frac{5000}{0.385\times100}=\frac{5000}{38.5}\approx129.9g$

Answer:

$129.9g$