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Question
cos 24 = x / 12
tan 24 = x / 12
sin 24 = x / 12
which is the correct set up to solve for x?
Step1: Recall trigonometric - ratio definitions
In a right - triangle, $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$, $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$, and $\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}$. For an angle of $24^{\circ}$ in the given right - triangle, the side opposite the $24^{\circ}$ angle is $x$ and the side adjacent to the $24^{\circ}$ angle is $12$.
Step2: Determine the correct trigonometric ratio
Since $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$, when $\theta = 24^{\circ}$, $\text{opposite}=x$ and $\text{adjacent}=12$, we have $\tan24^{\circ}=\frac{x}{12}$.
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$\tan24 = x/12$