Question

a crate of medicine with a density of 2,400 kilograms per cubic meter will be shipped from israel to the u.s. what is the crates density in pounds per cubic foot? first fill in the two blanks on the left - hand side of the equation using two of the ratios. then write your answer rounded to the nearest hundredth on the right - hand side of the equation.
ratios:
1 m³/2400 kg ×
1 kg/2.2 lb
2.2 lb/1 kg
1 m³/35.3 ft³
35.3 ft³/1 m³
= ft³/lb

Explanation:

Step1: Convert kg to lb

We know that 1 kg = 2.2 lb. We start with the density $\frac{2400\ kg}{1\ m^{3}}$. To convert the mass - unit from kg to lb, we multiply by the ratio $\frac{2.2\ lb}{1\ kg}$.
$\frac{2400\ kg}{1\ m^{3}}\times\frac{2.2\ lb}{1\ kg}$

Step2: Convert $m^{3}$ to $ft^{3}$

We know that 1 $m^{3}$ = 35.3 $ft^{3}$. To convert the volume - unit from $m^{3}$ to $ft^{3}$, we multiply by the ratio $\frac{1\ m^{3}}{35.3\ ft^{3}}$.
$\frac{2400\ kg}{1\ m^{3}}\times\frac{2.2\ lb}{1\ kg}\times\frac{1\ m^{3}}{35.3\ ft^{3}}$

Step3: Calculate the density in $\frac{lb}{ft^{3}}$

First, cancel out the units: The kg and $m^{3}$ units cancel out.
$\frac{2400\times2.2}{35.3}\frac{lb}{ft^{3}}=\frac{5280}{35.3}\frac{lb}{ft^{3}}\approx149.57\frac{lb}{ft^{3}}$

Answer:

The first blank is $\frac{2.2\ lb}{1\ kg}$, the second blank is $\frac{1\ m^{3}}{35.3\ ft^{3}}$, and the density is approximately 149.57 $\frac{lb}{ft^{3}}$