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Question
- a delivery van travels along a straight road. during the time interval 0 ≤ t ≤ 30 seconds, the van’s velocity in feet per second is a continuous function. use the table below to find the minimum number of times that the van must have been stopped. justify your answer.
| t (sec) | 0 | 5 | 7 | 12 | 18 | 22 | 30 |
| v(t) (ft/sec) | -28 | -60 | -15 | 8 | 24 | -4 | 10 |
Step1: Recall the condition for stopping
The van is stopped when \(V(t)=0\). Since \(V(t)\) is a continuous function, by the Intermediate - Value Theorem, if \(V(t)\) changes sign (from negative to positive or from positive to negative) over an interval, then \(V(t)\) must be \(0\) at some point in that interval.
Step2: Check sign - changes
At \(t = 0\), \(V(0)=- 28\) (negative), at \(t = 5\), \(V(5)=-60\) (negative), at \(t = 7\), \(V(7)=-15\) (negative), at \(t = 12\), \(V(12)=8\) (positive). Since \(V(t)\) changes sign from negative to positive between \(t = 7\) and \(t = 12\), \(V(t)=0\) at least once in the interval \((7,12)\).
At \(t = 18\), \(V(18)=24\) (positive), at \(t = 22\), \(V(22)=-4\) (negative). Since \(V(t)\) changes sign from positive to negative between \(t = 18\) and \(t = 22\), \(V(t)=0\) at least once in the interval \((18,22)\).
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The van must have been stopped at least 2 times.