Question

**i can determine if an ordered pair is a solution to a system.
determine if the ordered pair is a solution of the system or not. justify your answer by showing your work.

1. $y = x - 4$ $(1, -3)$

$y = -3x$

1. $y = x + 20$ $(-4, 24)$

$y = 6x$

1. $y = -x - 4$ $(2, -2)$

$y = x$

1. $y = x - 6$ $(-6, -12)$

$y = 2x$

Explanation:

Problem 27

Step 1: Check first equation

Substitute \( x = 1 \), \( y=-3 \) into \( y=x - 4 \).
Left side: \( y=-3 \), Right side: \( 1-4=-3 \). So, \( -3=-3 \), holds true.

Step 2: Check second equation

Substitute \( x = 1 \), \( y = -3 \) into \( y=-3x \).
Left side: \( y=-3 \), Right side: \( -3\times1=-3 \). So, \( -3=-3 \), holds true.

Step 1: Check first equation

Substitute \( x=-4 \), \( y = 24 \) into \( y=x + 20 \).
Left side: \( y = 24 \), Right side: \( -4+20 = 16 \). Since \( 24
eq16 \), the first equation fails.

Step 1: Check first equation

Substitute \( x = 2 \), \( y=-2 \) into \( y=-x - 4 \).
Left side: \( y=-2 \), Right side: \( -2-4=-6 \). Since \( -2
eq - 6 \), the first equation fails.

Answer:

\((1, - 3)\) is a solution.

Problem 28