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determine the value of y, if x is 81. y = \\sqrt{x}+12

Question

determine the value of y, if x is 81.
y = \sqrt{x}+12

Explanation:

Step1: Substitute x value

Substitute $x = 81$ into the equation $y=\sqrt{x}+12$. So we get $y=\sqrt{81}+12$.

Step2: Calculate square - root

We know that $\sqrt{81}=9$ since $9\times9 = 81$. So the equation becomes $y = 9+12$.

Step3: Calculate sum

$y=9 + 12=21$.

Answer:

21