QUESTION IMAGE
Question
in the diagram, lines m and n are parallel, and the angles have the measures shown. what is m∠1 in degrees? (3x + 2)° (5x + 18)°
Step1: Use angle - relationship of parallel lines
Since lines \(m\) and \(n\) are parallel, the angles \((5x + 18)^{\circ}\) and \((3x+2)^{\circ}\) are supplementary. So, \((5x + 18)+(3x + 2)=180\).
Step2: Solve the equation for \(x\)
Combine like - terms: \(5x+3x+18 + 2=180\), which simplifies to \(8x+20 = 180\). Subtract 20 from both sides: \(8x=180 - 20=160\). Then divide both sides by 8: \(x=\frac{160}{8}=20\).
Step3: Find the measure of one of the angles
Substitute \(x = 20\) into \((3x + 2)\): \(3x+2=3\times20 + 2=60 + 2=62^{\circ}\).
Step4: Find the measure of \(\angle1\)
\(\angle1\) and the angle \((3x + 2)^{\circ}\) are vertical angles. Vertical angles are equal. So \(m\angle1=(3x + 2)^{\circ}\). Since \(x = 20\), \(m\angle1=62^{\circ}\).
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\(62^{\circ}\)