Question

the diagram shows parallel lines a and b cut by transversals c and d. m∠5 = 85° m∠3 = 115° what are the measures of ∠2, ∠12, and ∠16? use the drop - down menus to identify each angle measure. m∠2 = choose... m∠12 = choose... m∠16 = choose...

Explanation:

Step1: Find measure of ∠2

∠2 and ∠3 are supplementary (linear - pair). Since m∠3 = 115°, then m∠2=180° - 115° = 65°.

Step2: Find measure of ∠12

∠5 and ∠12 are corresponding angles. Since parallel lines a and b are cut by transversal d and m∠5 = 85°, then m∠12 = 85°.

Step3: Find measure of ∠16

∠16 and ∠3 are alternate - exterior angles. Since parallel lines a and b are cut by transversal c and m∠3 = 115°, then m∠16 = 115°.

Answer:

m∠2 = 65°
m∠12 = 85°
m∠16 = 115°