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Question
- diego tried to solve the equation $\frac{1}{3}(x + 15) = 3$. what was his mistake?
$\frac{1}{3}(x + 15) = 3$
$\frac{1}{3}x = -12$
$x = -4$
word dividing by
Step1: Correct first step: eliminate fraction
Multiply both sides by 3:
$$3 \times \frac{1}{3}(x+15) = 3 \times 3$$
$$x + 15 = 9$$
Step2: Identify Diego's error
Diego incorrectly transformed $\frac{1}{3}(x+15)=3$ to $\frac{1}{3}x=-12$; he failed to distribute the $\frac{1}{3}$ to the 15, and incorrectly manipulated the constant term when moving 15 to the right.
Step3: Solve the correct equation
Subtract 15 from both sides:
$$x = 9 - 15$$
$$x = -6$$
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Diego made two key mistakes:
- He did not properly distribute $\frac{1}{3}$ to both $x$ and 15 when starting to solve the equation.
- He incorrectly rearranged the constants, leading to an wrong intermediate step $\frac{1}{3}x=-12$.
The correct solution for $x$ is $-6$.