Question

directions:

1. complete the description of the motion of each line segment.

extra practice problem #7
position vs. time
describe the speed and direction of blue line based on its graph
type here
describe the speed and direction of purple line based on its graph
type here

Explanation:

For the top (black) line segment:

1. It has a constant negative slope, meaning constant speed (uniform motion) in the negative direction (toward decreasing position values). Calculate speed: $\text{Speed} = \frac{\Delta \text{Position}}{\Delta \text{Time}} = \frac{10\ \text{m} - 4\ \text{m}}{10\ \text{s} - 0\ \text{s}} = 0.6\ \text{m/s}$.
2. Starts at position 10 m and moves to 3 m over 10 seconds, so it moves left/backward at 0.6 m/s.

For the bottom (purple) line segment:

1. It has a constant negative slope, meaning constant speed (uniform motion) in the negative direction. Calculate speed: $\text{Speed} = \frac{\Delta \text{Position}}{\Delta \text{Time}} = \frac{6\ \text{m} - 0\ \text{m}}{10\ \text{s} - 0\ \text{s}} = 0.6\ \text{m/s}$.
2. Starts at position 6 m and moves to 0 m over 10 seconds, so it moves left/backward at 0.6 m/s.

Answer:

1. Black line segment: The object moves with a constant speed of 0.6 m/s in the negative (decreasing position) direction, starting at 10 meters and ending at 3 meters after 10 seconds.
2. Purple line segment: The object moves with a constant speed of 0.6 m/s in the negative (decreasing position) direction, starting at 6 meters and ending at 0 meters after 10 seconds.