QUESTION IMAGE
Question
directions: factor each polynomial
- $x^4 - 36$
Step1: Recognize as difference of squares
The polynomial \(x^4 - 36\) can be written as \((x^2)^2 - 6^2\), which is a difference of squares \(a^2 - b^2=(a + b)(a - b)\) where \(a = x^2\) and \(b = 6\).
\(x^4 - 36=(x^2 + 6)(x^2 - 6)\)
Step2: Check if further factoring is possible
Now, \(x^2 - 6\) is also a difference of squares (\(x^2-(\sqrt{6})^2\)), so we can factor it further using the same formula. \(x^2 - 6=(x+\sqrt{6})(x - \sqrt{6})\)
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\((x^2 + 6)(x+\sqrt{6})(x - \sqrt{6})\)