Question

divide. $(4x^{2}+16x + 21)div(2x + 4)$ your answer should give the quotient and the remainder. quotient: remainder:

Explanation:

Step1: Divide first - term of dividend by first - term of divisor

$\frac{4x^{2}}{2x}=2x$

Step2: Multiply divisor by the result and subtract from dividend

$(4x^{2}+16x + 21)-(2x(2x + 4))=(4x^{2}+16x + 21)-(4x^{2}+8x)=8x + 21$

Step3: Divide new first - term by first - term of divisor

$\frac{8x}{2x}=4$

Step4: Multiply divisor by the new result and subtract from new dividend

$(8x + 21)-4(2x + 4)=(8x + 21)-(8x+16)=5$

Answer:

Quotient: $2x + 4$
Remainder: $5$