Question

draw the image of quadrilateral abcd under a translation by 1 unit to the right and 4 units up.

Explanation:

Step1: Recall translation rule

For a point $(x,y)$ translated 1 unit right and 4 units up, the new - point is $(x + 1,y+4)$.

Step2: Translate point A (assume coordinates are not shown, but the general method is as follows)

If the coordinates of point A are $(x_A,y_A)$, the new coordinates $A'=(x_A + 1,y_A + 4)$.

Step3: Translate point B

If $B=(x_B,y_B)=(-4,3)$, then $B'=(x_B + 1,y_B + 4)=(-4 + 1,3 + 4)=(-3,7)$.

Step4: Translate point C

If $C=(6,2)$, then $C'=(6 + 1,2 + 4)=(7,6)$.

Step5: Translate point D

If $D=(6,-2)$, then $D'=(6 + 1,-2 + 4)=(7,2)$.

Step6: Plot the new points

Plot the points $A'$, $B'$, $C'$, and $D'$ on the same coordinate - grid and connect them in order to form the translated quadrilateral.

Answer:

Plot the points obtained by adding 1 to the x - coordinates and 4 to the y - coordinates of the vertices of quadrilateral ABCD and connect them to form the new quadrilateral.