Question

the end of a hose was resting on the ground, pointing up an angle. sal measured the path of the water coming out of the hose and found that it could be modeled using the equation $f(x) = -0.3x^2 + 2x$, where $f(x)$ is the height of the path of the water above the ground, in feet, and $x$ is the horizontal distance of the path of the water from the end of the hose, in feet. when the water was 4 feet from the end of the hose, what was its height above the ground? \\(\bigcirc\\) 3.2 feet \\(\bigcirc\\) 4.8 feet \\(\bigcirc\\) 5.6 feet \\(\bigcirc\\) 6.8 feet

Explanation:

Step1: Substitute x=4 into the function

Substitute $x=4$ into $f(x) = -0.3x^2 + 2x$

Step2: Calculate the squared term

$x^2 = 4^2 = 16$

Step3: Compute the quadratic part

$-0.3 \times 16 = -4.8$

Step4: Compute the linear part

$2 \times 4 = 8$

Step5: Sum the two parts

$-4.8 + 8 = 3.2$

Answer:

3.2 feet