Question

the equation of the line is $y = \frac{4}{3}x + 7$. there is a coordinate plane with two lines: one is $y = \frac{4}{3}x + 7$ and the other is $y = -\frac{4}{3}x - 1$. there is an answer section and a solution: section with a text box and a submit answer button.

Explanation:

Step1: Set equations equal

$$\frac{4}{3}x + 7 = -\frac{4}{3}x - 1$$

Step2: Combine like terms

$$\frac{4}{3}x + \frac{4}{3}x = -1 - 7$$
$$\frac{8}{3}x = -8$$

Step3: Solve for x

$$x = -8 \times \frac{3}{8}$$
$$x = -3$$

Step4: Find y with x=-3

$$y = \frac{4}{3}(-3) + 7$$
$$y = -4 + 7$$
$$y = 3$$

Answer:

The intersection point of the two lines is $(-3, 3)$