Question

does the equation $6x + 3 = 5(x + 3)$ have one solution, no solutions, or infinitely many solutions?
$6x + 3 = 5(x + 3)$
$6x + 3 = 5x + 15$
$-5x \quad \quad -5x$
$x + 3 = 15$
$x = \square$

Explanation:

Step1: Expand right-hand side

$6x + 3 = 5x + 15$

Step2: Subtract $5x$ from both sides

$6x + 3 - 5x = 5x + 15 - 5x$
$x + 3 = 15$

Step3: Subtract 3 from both sides

$x + 3 - 3 = 15 - 3$
$x = 12$

Answer:

The equation has one solution: $x = 12$