Question

an equation is shown.
$(6^{n})^{4}=6^{-12}$
what is the value of $n$
a 3
b -3
c 2
d -2

Explanation:

Step1: Apply exponent power rule

For $(a^m)^k = a^{m \times k}$, so $(6^n)^4 = 6^{4n}$.
Equation becomes: $6^{4n} = 6^{-12}$

Step2: Set exponents equal (same base)

Since bases are equal, exponents are equal: $4n = -12$

Step3: Solve for n

Divide both sides by 4: $n = \frac{-12}{4}$

Answer:

B. -3