Question

in the equation $4x^3 = 80$, what is the value of $x$?
express your answer numerically.
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$x = $
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part d
rearrange the equation $(z - 1)(z - 1)(z - 1) = y$ to solve for $z$
express $z$ in terms of $y$.
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Explanation:

Step1: Isolate $x^3$ term

Divide both sides by 4:
$\frac{4x^3}{4} = \frac{80}{4}$
$x^3 = 20$

Step2: Solve for $x$

Take cube root of both sides:
$x = \sqrt[3]{20}$
Calculate the numerical value:
$x \approx 2.714$

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Step1: Rewrite left-hand side

Simplify $(z-1)(z-1)(z-1)$ as a cube:
$(z-1)^3 = y$

Step2: Isolate $(z-1)$

Take cube root of both sides:
$z-1 = \sqrt[3]{y}$

Step3: Solve for $z$

Add 1 to both sides:
$z = \sqrt[3]{y} + 1$

Answer:

For $4x^3=80$: $x \approx 2.714$
For $(z-1)(z-1)(z-1)=y$: $z = \sqrt[3]{y} + 1$