Question

$3^{10}$
ether.
roots.
ponent by
t by
$(x^{2})$
$sqrt{3^{6}}$
$sqrt3{8^{6}}$
$sqrt3{x^{2}}$

Explanation:

Step1: Rewrite square root as exponent

$\sqrt{3^6} = 3^{\frac{6}{2}}$

Step2: Simplify the exponent

$3^{\frac{6}{2}} = 3^3 = 27$

Step3: Rewrite cube root as exponent

$\sqrt[3]{8^6} = 8^{\frac{6}{3}}$

Step4: Simplify the exponent

$8^{\frac{6}{3}} = 8^2 = 64$

Step5: Rewrite cube root as exponent

$\sqrt[3]{x^2} = x^{\frac{2}{3}}$

Answer:

$\sqrt{3^6}=27$, $\sqrt[3]{8^6}=64$, $\sqrt[3]{x^2}=x^{\frac{2}{3}}$