Question

evaluate the function below at $x = -5$.
$f(x) = \

$$\begin{cases} \\frac{6}{x} + 7, & x = 5 \\\\ (x - 3)^2, & x = -5 \\\\ x^2 + 13, & x \ eq 5, -5 \\end{cases}$$

$
show your work here
$f(-5) = $
find the domain and range of the piecewise function graphed below. enter your answers in interval notation using the fewest number of intervals required.
draw

Explanation:

Step1: Identify the correct piece

For \( x = -5 \), we use the piece \( (x - 3)^2 \) since the function is defined as \( (x - 3)^2 \) when \( x = -5 \).

Step2: Substitute \( x = -5 \)

Substitute \( x = -5 \) into \( (x - 3)^2 \):
\[
(-5 - 3)^2 = (-8)^2
\]

Step3: Calculate the result

Calculate \( (-8)^2 \):
\[
(-8)^2 = 64
\]

Answer:

\( f(-5) = 64 \)