Question

a. evaluate f(5) given that f(x) = (x^2+(16 - 5x))/(8x).
f(5) = 0.4
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b. evaluate g(x + 3) given that g(x)=3x^2 - 6x + 9.
g(x + 3)=3x^2+12x+18
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c. evaluate h(3x) given that h(y)=(y^3 - 6)/(8y).
h(3x)=
enter an algebraic expression more...
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question 6. points possible: 3
unlimited attempts.

Explanation:

Step1: Substitute $y = 3x$ into $h(y)$

Substitute $y$ with $3x$ in $h(y)=\frac{y^{3}-6}{8y}$, we get $h(3x)=\frac{(3x)^{3}-6}{8\times(3x)}$.

Step2: Simplify the numerator

$(3x)^{3}=3^{3}\times x^{3}=27x^{3}$, so the numerator is $27x^{3}-6$.

Step3: Simplify the denominator

$8\times(3x) = 24x$.

Step4: Write the final expression

$h(3x)=\frac{27x^{3}-6}{24x}=\frac{9x^{3}-2}{8x}$.

Answer:

$\frac{9x^{3}-2}{8x}$