Question

evaluate the limit
lim_{u
ightarrow3}sqrt{u^{2}+3u + 7}
enter i for (infty), -i for (-infty), and dne if the limit does not exist.
limit =

Explanation:

Step1: Substitute $u = 3$

Substitute $u = 3$ into $u^{2}+3u + 7$. We get $3^{2}+3\times3 + 7$.

Step2: Calculate the value inside the square - root

$3^{2}+3\times3 + 7=9 + 9+7=25$.

Step3: Calculate the square - root

$\sqrt{25}=5$.

Answer:

$5$