Question

1. evaluate $5a^{3}-6a + 7a^{2}-8a^{3}-3a + 5a^{2}-12 + 11a + 4$ when $a=-1$ 10 pts

Explanation:

Step1: Combine like $a^3$ terms

$5a^3 - 8a^3 = -3a^3$

Step2: Combine like $a^2$ terms

$7a^2 + 5a^2 = 12a^2$

Step3: Combine like $a$ terms

$-6a - 3a + 11a = 2a$

Step4: Combine constant terms

$-12 + 4 = -8$

Step5: Substitute $a=-1$

$-3(-1)^3 + 12(-1)^2 + 2(-1) - 8$

Step6: Calculate each term

$-3(-1) + 12(1) + (-2) - 8 = 3 + 12 - 2 - 8$

Step7: Compute final sum

$3+12-2-8=5$

Answer:

$5$