Question

evaluate $6t - 20 - 32u$ when $t = 6$ and $u = \frac{1}{4}$.

Explanation:

Step1: Substitute t and u values

Substitute \( t = 6 \) and \( u=\frac{1}{4} \) into the expression \( 6t - 20 - 32u \).
\[
6\times6 - 20 - 32\times\frac{1}{4}
\]

Step2: Calculate each term

Calculate \( 6\times6 = 36 \), \( 32\times\frac{1}{4}=8 \).
\[
36 - 20 - 8
\]

Step3: Perform subtraction

First, \( 36 - 20 = 16 \), then \( 16 - 8 = 8 \).

Answer:

\( 8 \)