Question

exit ticket:

1. which point is the vertex of ( f(x) = 16(x - 19)^2 - 20 )?

a ( (-19, -20) )
b ( (16, -20) )
c ( (19, -20) )
d ( (19, 20) )

Explanation:

Step1: Recall vertex form of parabola

The vertex form of a quadratic function is \( f(x) = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

Step2: Identify \(h\) and \(k\) from given function

For the function \( f(x) = 16(x - 19)^2 - 20 \), comparing with the vertex form \( f(x) = a(x - h)^2 + k \), we have \( h = 19 \) and \( k = -20 \).

Step3: Determine the vertex

So the vertex of the parabola is \((h, k)=(19, -20)\).

Answer:

C. (19, -20)