Question

in an experiment, a photon with a frequency of 7 × 10^14 s^(-1) was absorbed by a sample. what is the approximate energy of this photon?
a 5 × 10^(-19) j
b 1 × 10^(-15) j
c 2 × 10^6 j
d 1 × 10^48 j

Explanation:

Step1: Recall energy - frequency formula

The energy of a photon is given by $E = h
u$, where $h = 6.63\times10^{-34}\text{ J}\cdot\text{s}$ (Planck's constant) and $
u$ is the frequency of the photon.

Step2: Substitute values

Given $
u = 7\times 10^{14}\text{ s}^{-1}$ and $h = 6.63\times10^{-34}\text{ J}\cdot\text{s}$, then $E=(6.63\times 10^{-34}\text{ J}\cdot\text{s})\times(7\times 10^{14}\text{ s}^{-1})$.

Step3: Perform calculation

$E=(6.63\times7)\times10^{-34 + 14}\text{ J}=46.41\times10^{-20}\text{ J}\approx4.64\times 10^{-19}\text{ J}\approx5\times 10^{-19}\text{ J}$.

Answer:

A. $5\times 10^{-19}\text{ J}$