Question

1. explain the type of motion that will occur based on the amount of force.

a. does it move: yes no
b. which direction does it move: right left no direction
c. why?

1. explain the type of motion that will occur based on the amount of force.

a. does it move: yes no
b. which direction does it move: right left no direction
c. why?

1. explain the type of motion that will occur based on the amount of force.

a. does it move: yes no
b. which direction does it move: right left no direction
c. why?
(images of force vectors: 7n downward, 11n upward; 2n upward, 12n downward; 3n downward, 3n upward)

Explanation:

Question 6

Step1: Calculate net vertical force

$F_{net, vertical} = 11\,\text{N} - 7\,\text{N} = 4\,\text{N (upward)}$

Step2: Calculate net horizontal force

$F_{net, horizontal} = 0\,\text{N}$

Step3: Determine motion and direction

Since net force is non-zero, the object moves, in the direction of the net force (upward, which is the "No Direction" option's equivalent here as the given horizontal options don't match, but the vertical net force causes motion upward; however, based on the options, we use the vertical logic)

Step1: Calculate net vertical force

$F_{net, vertical} = 2\,\text{N} - 2\,\text{N} = 0\,\text{N}$

Step2: Calculate net horizontal force

$F_{net, horizontal} = 12\,\text{N}$ (rightward)

Step3: Determine motion and direction

Net force is non-zero, so object moves right.

Step1: Calculate net vertical force

$F_{net, vertical} = 3\,\text{N} - 3\,\text{N} = 0\,\text{N}$

Step2: Calculate net horizontal force

$F_{net, horizontal} = 0\,\text{N}$

Step3: Determine motion and direction

Net force is zero, so object does not move.

Answer:

a. Yes
b. No Direction (moves upward, as vertical net force is non-zero)
c. The net vertical force is $11\,\text{N} - 7\,\text{N} = 4\,\text{N}$ upward, so there is an unbalanced force, causing the object to move.

---

Question 7