Question

express the trig ratios as fractions in simplest terms.
answer attempt 1 out of 2
sin $o = \square$
cos $n = \square$
sin $o$ and cos $n$
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Explanation:

Step1: Recall sine definition

For angle $O$, $\sin O = \frac{\text{opposite}}{\text{hypotenuse}}$
$\sin O = \frac{MN}{ON} = \frac{41}{42}$

Step2: Recall cosine definition

For angle $N$, $\cos N = \frac{\text{adjacent}}{\text{hypotenuse}}$
$\cos N = \frac{MN}{ON} = \frac{41}{42}$

Answer:

$\sin O = \frac{41}{42}$, $\cos N = \frac{41}{42}$