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is the expression ((s + t)^2) equivalent to (s^2 + 2st + t^2)?

Question

is the expression ((s + t)^2) equivalent to (s^2 + 2st + t^2)?

Explanation:

Step1: Expand the left-hand side

$(s+t)^2 = (s+t)(s+t)$

Step2: Distribute terms (FOIL method)

$(s+t)(s+t) = s^2 + st + ts + t^2$

Step3: Combine like terms

$s^2 + st + ts + t^2 = s^2 + 2st + t^2$

Step4: Compare both sides

Left-hand side equals right-hand side.

Answer:

Yes