Question

extra practice: given the function f(x) = x³ + 7 what is the value of f(6)? f(x)=x³+7 f(6)=6³+7 f(6)=26 input: ____ output: __ given the function k(x) = 2x² - 5x + 3 what is the value of k(1)? input: __ output: ____

Explanation:

First Sub - Question (Finding \( f(6) \) for \( f(x)=x^{3}+7 \))

Step 1: Substitute \( x = 6 \) into the function

We have the function \( f(x)=x^{3}+7 \). To find \( f(6) \), we replace \( x \) with 6 in the function. So we get \( f(6)=6^{3}+7 \).

Step 2: Calculate \( 6^{3} \)

We know that \( 6^{3}=6\times6\times6 = 216 \).

Step 3: Add 7 to the result

Now we add 7 to 216. So \( f(6)=216 + 7=223 \).

Step 1: Substitute \( x = 1 \) into the function

We have the function \( k(x)=2x^{2}-5x + 3 \). To find \( k(1) \), we replace \( x \) with 1 in the function. So we get \( k(1)=2\times(1)^{2}-5\times(1)+3 \).

Step 2: Calculate each term

First, \( (1)^{2}=1 \), so \( 2\times(1)^{2}=2\times1 = 2 \). Then, \( 5\times(1)=5 \).

Step 3: Simplify the expression

Now we substitute these values back into the expression: \( k(1)=2-5 + 3 \). First, \( 2-5=-3 \), and then \( -3 + 3 = 0 \).

Answer:

\( f(6)=223 \)

Second Sub - Question (Finding \( k(1) \) for \( k(x)=2x^{2}-5x + 3 \))